Sql difference between two numbers

Sql difference between two numbers DEFAULT

How to find absolute difference between two numbers in MySQL?


To get the difference between two number in MySQL, let us first create a demo table

mysql> create table findDifferenceDemo -> ( -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, -> FirstNumber float, -> SecondNumber float -> ); Query OK, 0 rows affected (0.60 sec)

Insert some records in the table using insert command. The query is as follows −

mysql> insert into findDifferenceDemo(FirstNumber,SecondNumber) values(4.2,2.3); Query OK, 1 row affected (0.20 sec) mysql> insert into findDifferenceDemo(FirstNumber,SecondNumber) values(23.4,5.6); Query OK, 1 row affected (0.14 sec) mysql> insert into findDifferenceDemo(FirstNumber,SecondNumber) values(5.8,34.56); Query OK, 1 row affected (0.16 sec) mysql> insert into findDifferenceDemo(FirstNumber,SecondNumber) values(7.8,7.2); Query OK, 1 row affected (0.16 sec) mysql> insert into findDifferenceDemo(FirstNumber,SecondNumber) values(12.8,10.2); Query OK, 1 row affected (0.13 sec)

Display all records from the table using select statement. The query is as follows −

mysql> select *from findDifferenceDemo;

The following is the output

+----+-------------+--------------+ | Id | FirstNumber | SecondNumber | +----+-------------+--------------+ | 1 | 4.2 | 2.3 | | 2 | 23.4 | 5.6 | | 3 | 5.8 | 34.56 | | 4 | 7.8 | 7.2 | | 5 | 12.8 | 10.2 | +----+-------------+--------------+ 5 rows in set (0.00 sec)

The following is the query to find absolute difference between two numbers in MySQL

mysql> SELECT ABS(FirstNumber - secondNumber) AS diff -> from findDifferenceDemo -> order by diff desc;

The following is the output

+--------------------+ | diff | +--------------------+ | 28.760001182556152 | | 17.799999713897705 | | 2.6000003814697266 | | 1.8999998569488525 | | 0.6000003814697266 | +--------------------+ 5 rows in set (0.00 sec)
Sours: https://www.tutorialspoint.com/how-to-find-absolute-difference-between-two-numbers-in-mysql

SQL Server DIFFERENCE() Function

❮ SQL Server Functions

Example

Compares two SOUNDEX values, and return an integer:

SELECT DIFFERENCE('Juice', 'Jucy');

Try it Yourself »

Definition and Usage

The DIFFERENCE() function compares two SOUNDEX values, and returns an integer. The integer value indicates the match for the two SOUNDEX values, from 0 to 4.

0 indicates weak or no similarity between the SOUNDEX values. 4 indicates strong similarity or identically SOUNDEX values.

Tip: Also look at the SOUNDEX() function.

Syntax

DIFFERENCE(expression, expression)

Parameter Values

ParameterDescription
expression, expressionRequired. Two expressions to be compared. Can be a constant, variable, or column

Technical Details

Works in:SQL Server (starting with 2008), Azure SQL Database, Azure SQL Data Warehouse, Parallel Data Warehouse

More Examples

Example

Compares two SOUNDEX values, and return an integer:

SELECT DIFFERENCE('Juice', 'Banana');

Try it Yourself »

❮ SQL Server Functions


Sours: https://www.w3schools.com/sql/func_sqlserver_difference.asp
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Calculating the difference between two rows in SQL can be a challenging task. It is possible – and there’s more than one way to do it. In this article, I’ll explain how to use the SQL window functions and to find the difference between two rows in the same table.

I like to think of this as a “happy hour" article – you can learn about two topics (calculating the difference between two rows and SQL window functions) by reading just one article. Let’s get right into it!

Find the Difference Between Two Values in the Same Row

To calculate any difference, you need two elements; to calculate a difference in SQL, you need two records. You can calculate the difference between two columns in the same record, as I’ll show in a moment. It’s very easy. However, I’ll mainly focus on finding the difference between two values of the same column in different records.

First, let’s talk about our data. We’ll use a database with two tables, as used by the government of an imaginary province to define some social programs. The first table is , which contains data about the number of people renting, owning, or needing a house. Have a look:

Table

CityYearTotal PopulationPopulation Owning housePopulation renting housePopulation needing house
Goldpolis201722501500500250
Silverpolis201717501200400150
Bronzepolis201714201000300120
Goldpolis201824251600550275
Silverpolis201819201300410210
Bronzepolis201817301020300410
Goldpolis201926101750580280
Silverpolis201921101400420290
Bronzepolis201920101050300660

To design a plan to build houses for people who need them, the government wants to obtain some metrics about the housing problems in different cities. Suppose the government wants to know how many people in each city don’t own a house; the query will be:

SELECT city, total_population, total_population - population_owning_house AS people_not_owning_house FROM housing

In this query, it’s clear you’re calculating a difference using two different columns in the same record. Next, you’ll calculate differences using two records.

Calculating the Difference Between Two Values in the Same Column

Usually, all the operations we do in a SQL query are related to the current record. But in this case, we need a second record. This is the tricky part. We’ll use a technique that employs the windows functions and to obtain data from another record. If you want to go deeper, I suggest reading this window functions article that gives clear explanations of window functions with plenty of examples.

Let’s suppose that, for one specific city ( ‘Bronzepolis’ ), you want to obtain the variation of people needing a house related to the previous year. Let’s see the query:

SELECT city, year, population_needing_house, LAG(population_needing_house) AS previous_year population_needing_house - LAG(population_needing_house) OVER (ORDER BY year ) AS difference_previous_year FROM housing WHERE city = ‘Bronzepolis’ ORDER BY year

In the blue text, you can see the calculation of the SQL delta between two rows. To calculate a difference, you need a pair of records; those two records are “the current record” and “the previous year’s record”. You obtain this record using the window function. This function allows you to obtain data from the previous record (based on an order criterion, which here is “”).

LAG

Below is the result of this query. The red arrows show that the value of the function returns the same population_needing_house value as the previous year’s record. The column at the right shows the result of the difference between the current and previous years.

LAG

For the next query, we’ll expand the analysis of housing issues to all cities. For each city, we want the difference between the current and previous years for the column.

First, you’ll remove the condition . You want to calculate values for each city, so you need a way to separate data into groups. This is why you add the city clause to . allows you to process all the records for the same city in the same window.

You’ll use again to calculate the difference between the number of people needing a house between this year and the previous year. Let’s see the query:

SELECT city, year, population_needing_house, LAG(population_needing_house) OVER (PARTITION BY city ORDER BY year ) AS previous_year population_needing_house - LAG(population_needing_house) OVER (PARTITION BY city ORDER BY year ) AS difference_previous_year FROM housing ORDER BY city, year

In blue text, you can see how the difference is calculated. Here’s a plain-English version of what’s going on:

difference_previous_year = population_needing_house in current record - population_needing_house in the previous year’s record

Where:

Population_needing_house in the current record is the column

and

Population_needing_house in the previous year’s record is obtained by the function

CityYearPopulationPrevious YearDifference previous year
needing2019660410250
housePrevious YearDifference150290
previous2017150nullnull
year201824251600550
Bronzepolis2017150nullnull
Bronzepolis2018410150290
Bronzepolis2019660410250
Goldpolis2017250nullnull
Goldpolis201827525025
Goldpolis20192802755
Silverpolis2017150nullnull
Silverpolis201821015060
Silverpolis201929021080

So, you've used the clause to create a set with all the records for the same city. Then the clause is used to order all these records by year. Finally, the function is used to obtain the value from the previous record.

Another SQL window function, , is similar to . However, it returns the next record in the set (in our example, this would be the next year’s record).

If you review the two previous queries, you’ll see that we use the same pattern to calculate the difference: subtracting the previous column value from the current value using (or from the next record using ).

SQL window functions are very powerful. To learn more, check out this article on when to use SQL window functions. It provides examples from different business areas, like finance, sales, and trading.

Calculating the Difference Between Date Values in SQL

In the previous examples, you calculated the delta between two rows using numeric column values. Now I’ll demonstrate how to calculate the difference between two values of the date data type.

First, let’s consider the result’s data type. When you calculate the difference between two date values, the result is not a date. It is an interval that represents the number of days between the two dates.

Suppose there’s a table called that stores statistics for the province’s three hospitals. Below is a sample of the table data:

Table

Hospital namedayillnessnumber of patients
Hospital of Bronzepolis2017-03-22MDLR1
Hospital of Goldpolis2017-12-03MDLR1
Hospital of Silverpolis2018-08-03MDLR1
Hospital of Bronzepolis2019-01-23MDLR1
Hospital of Goldpolis2019-06-14MDLR1

Now let’s say there’s a rare illness called MDLR. The government wants to study how often a patient with MDLR is admitted to any of the hospitals. They’ve asked for a report with the columns , , , and . We’ll use SQL to build the report:

SELECT day, hospital_name, number_of_patients, day - LAG(day) OVER (ORDER BY day) AS days_since_last_case FROM hospital_statistics WHERE illness_name = 'MDLR' ORDER BY day

You can see the same pattern that we used before. Now, it’s being used to calculate the days since the last case. The only difference is that you’re calculating a difference between two dates instead of numeric values.

As you see in the results, the column is an integer value, representing a number of days.

DayHospital NameIllnessPatientsdays_since_last_case
2017-03-22Hospital of BronzepolisMDLR1null
2017-12-03Hospital of GoldpolisMDLR1256
2018-08-03Hospital of SilverpolisMDLR1243
2019-01-23Hospital of BronzepolisMDLR1173
2019-06-14Hospital of GoldpolisMDLR1142

SQL also allows you to calculate differences between values. And there are other interesting date arithmetic operations you can use on date-related data types. If you want to go deeper, I suggest the article How to Analyze Time Series COVID 19 Data with SQL Window Functions.

Finding the Difference Between Non-Consecutive Records

Until now, you’ve calculated differences between contiguous records based on specific order criteria. In some cases, you’ll need to calculate the difference between non-contiguous records.

As an example, let’s go back to the first query. Suppose we want to add another column showing the number of cases in the last two years. Fortunately, and has an optional parameter that specifies how many records to skip before/after the current record. By default, this parameter is 1 (i.e. “use the next/previous record”), but you can set it to another number. So, with this new parameter, the query will be:

SELECT city, year, population_needing_house, LAG(population_needing_house) OVER (PARTITION BY city ORDER BY year ) AS one_year_before, LAG(population_needing_house,2) OVER (PARTITION BY city ORDER BY year ) AS two_years_before, population_needing_house - LAG(population_needing_house) OVER (PARTITION BY city ORDER BY year ) AS difference_previous_year, population_needing_house - LAG(population_needing_house,2) OVER (PARTITION BY city ORDER BY year ) AS difference_last_two_years FROM housing ORDER BY 1 , 2 DESC

In blue, you can see the calculation of the difference between two non-consecutive records. In the next image, we can see the new column only for the 2019 values; this is because 2019 is the only year that has data for two prior years. The red lines connect the function’s results (obtaining data for 2017 and showing the same data in the 2017 record). You can see that both lines have the same value.

LAG

We’ve shown how important and are, but there are many more window functions in SQL. I suggest the following article about window functions to get some background on them.

More About SQL Calculations and Window Functions

In this article, you’ve learned how to calculate the difference between consecutive rows by applying SQL. You’ve also learned how to use and to find the difference between non-consecutive rows. Although there are other ways to calculate this difference, such as using a self-join, these methods are very useful.

If you will be using windows functions (or indeed SQL) frequently – or if you just want to improve your knowledge – this complete window functions cheat sheet is an excellent resource. Or, for an interactive learning experience, try our Window Functions course.

Sours: https://learnsql.com/blog/difference-between-two-rows-in-sql/
Find percentage difference between two numbers - In Excel

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How to work out the difference of two numbers in SQL table.

Transact-SQLhttps://social.msdn.microsoft.com/Forums/sqlserver/en-US/8c329df8-bde1-4503-a6c5-9ec42a60d62d/how-to-work-out-the-difference-of-two-numbers-in-sql-table?forum=transactsqlQuestion97/11/2006 6:52:15 AM12/12/2008 5:43:16 AMTSQL challenges? This is the place for advice and discussions00

  • Question

  • text/html7/11/2006 6:52:15 AMSibusisok0

    Hi

    I have 2 columns the first column is a counter thats always counting up like a meter, the second column is a formula that calculate the difference between the counter(column one). like

    CounterDifference
    11
    32
    63
    93
    112
    132
    174
    258

    The first row is taken as it is, but the second row will be difference = 3-1 the third one will be 3-6 and so on.

    How can I do this in a SQL table or any other away?

    Your help will be highly appreciated.

Answers

  • text/html7/15/2006 4:18:58 AMLouis Davidson0

    Here is a solution for 2005.  If you are using 2000, you can replace the CTE with a temp table and identity pretty easily:

    create table test
    (
        counter  int
    )
    insert into test
    select 1
    union all
    select 3
    union all
    select 6
    union all
    select 9
    union all
    select 11
    union all
    select 13
    union all
    select 17
    union all
    select 25
    go

    with rows as (
                           select row_number() over (order by counter) as rownum, counter
                           from   test)

    select rowsMinusOne.counter, 
               rowsMinusOne.counter - rows.counter as diff
    from   rows as rowsMinusOne
                    left outer join rows
                           on rows.rownum = rowsMinusOne.rownum - 1

    This returns this:

    counter     diff
    ----------- -----------
    1           NULL
    3           2
    6           3
    9           3
    11          2
    13          2
    17          4
    25          8

    I think the null is a better thing than 1 for the first row (but it is your call :)

All replies

  • text/html7/11/2006 7:35:41 AMSibusisok0

    Hi Jens, Thanks for your answer

    I will assume there will be a formula in the Difference column, I want as you enter the value first row in a Counter column it takes the value as it is to a Difference column and when the user enters the second value the difference will be calculated between the values and so on.

    I don't if im right about the formula but im willing to try any other way you fill can do thesame thing mybe stored procedure 

  • text/html7/12/2006 12:18:57 AMTailor0

    I understand what you are trying to achieve, but it would be most helpful if you told us how the user is going to insert the number in the counter row.

    If I were doing this in Visual Studio, I would be looking at using TextBox1 in Read Only to hold the last CounterNo,(SELECTED from the Sql table),  TextBox2 to insert the next CounterNo, then INSERT the  difference ( TextBox2-TextBox1 ) in the Difference column, along with TextBox2.Text in the Counter column when you update your table.

    This approach eliminates the need to track alternate rows in your table.

    HTH

    John

  • text/html7/12/2006 6:42:03 AMSibusisok0

    Thanks John

    I copy the Counter values from another SQL table using the Select into statement to the table explained in the first post. is there a way to write a SQL code to work out the this problem rather have to create  VStudio code to do this?

  • text/html7/12/2006 7:31:47 AMTailor0

    Your problem is not something I've done in straight SQL statements, so it may take some time to work it out.

    I had thought of using COMPUTE, or ROW_NUMBER with an ORDER BY clause but COMPUTE cannot be used with SELECT INTO, and ORDER BY will not necessarily give a correct result then, either.

    I've been looking at the possibility of having another column with numbers indexed by 1, but am not experienced enough to say that idea would work, and dont know the exact mechanins of what you are doing. I'm guessing you are transferring a number of records at once, correct.?.

    If someone else has the answers I'd like to hear them, but in the meantime I'll see what I can come up with. It may take a while, sorry.

    John

  • text/html7/14/2006 11:10:14 PMMike Wachal - MSFT0

  • text/html7/15/2006 4:18:58 AMLouis Davidson0

    Here is a solution for 2005.  If you are using 2000, you can replace the CTE with a temp table and identity pretty easily:

    create table test
    (
        counter  int
    )
    insert into test
    select 1
    union all
    select 3
    union all
    select 6
    union all
    select 9
    union all
    select 11
    union all
    select 13
    union all
    select 17
    union all
    select 25
    go

    with rows as (
                           select row_number() over (order by counter) as rownum, counter
                           from   test)

    select rowsMinusOne.counter, 
               rowsMinusOne.counter - rows.counter as diff
    from   rows as rowsMinusOne
                    left outer join rows
                           on rows.rownum = rowsMinusOne.rownum - 1

    This returns this:

    counter     diff
    ----------- -----------
    1           NULL
    3           2
    6           3
    9           3
    11          2
    13          2
    17          4
    25          8

    I think the null is a better thing than 1 for the first row (but it is your call :)

Sours: https://social.msdn.microsoft.com/Forums/sqlserver/en-US/8c329df8-bde1-4503-a6c5-9ec42a60d62d/how-to-work-out-the-difference-of-two-numbers-in-sql-table?forum=transactsql

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9 hours ago A more accurate, but not perfect, way to calculate age in years is to first work out the difference in days between two dates and then divide the result by the number of days in a year. The method is shown in the example below: Dividing the age in days by the number of days in a year gives a slightly more accurate result.

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How to compare tables in SQL Server SQL Shack

1 hours ago Using these two queries, we can see if the tables are identical or what their differences may be. If the number of rows in the first query (INERSECT) is the same as the number of rows in the Original and Revised tables, they are identical, at least for tables having keys (since there can be no duplicates).

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Generating random numbers and strings in Oracle

9 hours ago Generating random numbers or strings is oft-times a necessity. Oracle provides a random number generator that is faster than writing your won random generation logic in PL/SQL, and can generate both character and alphanumeric strings. Perhaps it is time to learn more about the DBMS_RANDOM package.

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Oracle NUMBER Data Type By Practical Examples

9 hours ago Code language: SQL (Structured Query Language) (sql) The Oracle NUMBER data type has precision and scale. The precision is the number of digits in a number. It ranges from 1 to 38. The scale is the number of digits to the right of the decimal point in a number. It ranges from -84 to 127. For example, the number 1234.56 has a precision of 6 and

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Difference between SQL and PLSQL GeeksforGeeks

3 hours ago It enables the systems personnel end-users to deal with a number of database management systems where it is available. Difference between Structured Query Language (SQL) and Transact-SQL (T-SQL) Recommended Articles. Page : Difference between Structured Query Language (SQL) and Transact-SQL (T-SQL) 22, Aug 19.

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SQL Query to find difference between row values of a

7 hours ago Hi, I have one table like ID Name Cost 1 Ram 2500 1 Raj 500 2 Ram 2500 2 Raj 5000 Now i need result table as ID Name Cost 1 Ram 2000 2 Raj -2500 Here the result should be difference between two row

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Date Duration Calculator: Days Between Dates

5 hours ago Date Calculators. Time and Date Duration – Calculate duration, with both date and time included. Date Calculator – Add or subtract days, months, years. Weekday Calculator – What Day is this Date? Birthday Calculator – Find when you are 1 billion seconds old. Week Number Calculator – Find the week number for any date.

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Relational AlgebraRelational CalculusSQL

4 hours ago 51 Key Differences Between SQL And “Pure” Relational Algebra SQL data model is a multiset not a set; still rows in tables (we sometimes continue calling relations) » Still no order among rows: no such thing as 1st row » We can (if we want to) …

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Difference between Cardinal, Ordinal and Nominal Numbers

Just Now Cardinal numbers are definite numerals and cannot contain fractions or decimals. However, in mathematics cardinal numbers have a slight different meaning. Cardinal refers to the measuring the cardinality (the number of elements present) of a set or between two sets. Even in this sense, cardinal numbers must have numerals or whole numbers.

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Coalesce Function SQL Server Example String concatenation

4 hours agoSQL Coalesce Function and Pivoting. A user-defined function is used to return a string specific to the given input and output is grouped together using the group clause. For this example, the scalar-valued functions return the concatenated string values separated by commas for specified inputs. In this example, state values are grouped, city

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How to Compare Two Columns in Excel For Finding Differences

2 hours ago We will see 4 different processes of finding the differences between the two columns. In every process, we will use the same table. Compare Two Columns in Excel For Differences using Conditional Formatting. We can use conditional formatting to highlight the unique values of two columns. The procedure is simple and given below.

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Compare And Find Data Differences Between Two Tables In

5 hours ago We can see here that despite the differences between the definitions of the Employee tables in two databases, the table columns that we need for comparison are identical in data type. This means that the difference in the schemas of the Employee tables is acceptable. That is, we can compare the data in these two tables.

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Difference Between SQL Vs MySQL Vs SQL Server (with Examples)

3 hours ago Having had the basic understanding of SQL and MySQL, by now you must have understood the basic difference between the twoSQL is a query language whereas MySQL is a database management system. Let’s see the differences between these two in detail.

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Working with Numbers in PL/SQL Oracle

4 hours agoNumbers in PL/SQL. PL/SQL offers a variety of numeric datatypes to suit different purposes: NUMBER. A true decimal datatype that is ideal for working with monetary amounts. NUMBER is the only one of PL/SQL’s numeric types to be implemented in a platform-independent fashion. PLS_INTEGER.

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REGEXP_LIKE Examples Oracle REGEXP_LIKE Complex SQL

8 hours ago The REGEXP_LIKE function is used to find the matching pattern from the specific string. Let us create a table named Employee and add some values in the table. Example 1: User wants to fetch the records, which contains letter ‘J’. The above scenario will be achieved by using REGEXP_LIKE function. SELECT *.

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How to work out the difference of two numbers in sql table?

The first row is taken as it is, but the second row will be difference = 3-1 the third one will be 3-6 and so on. How can I do this in a SQL table or any other away? Your help will be highly appreciated. Here is a solution for 2005. If you are using 2000, you can replace the CTE with a temp table and identity pretty easily:

How to find the difference between two character expressions in sql?

This function returns an integer value measuring the difference between the SOUNDEX () values of two different character expressions. To view Transact-SQL syntax for SQL Server 2014 and earlier, see Previous versions documentation. An alphanumeric expression of character data. character_expression can be a constant, variable, or column.

How to use difference function in sql server?

SQL Server DIFFERENCE () Function 1 Definition and Usage. The DIFFERENCE () function compares two SOUNDEX values, and returns an integer. The integer value indicates the match for the two SOUNDEX values, from 0 to 4. 2 Syntax 3 Parameter Values. Two expressions to be compared. 4 Technical Details 5 More Examples

What are the different types of numbers in sql?

In SQL, numbers are defined as either exact or approximate. The exact numeric data types are SMALLINT, INTEGER, BIGINT, NUMERIC (p,s), and DECIMAL (p,s). Exact SQL numeric data type means that the value is stored as a literal representation of the number's value. The approximate numeric data types are FLOAT (p), REAL, and DOUBLE PRECISION.

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SQL vs MySQL - Difference between SQL and MySQL - Intellipaat

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